Adding Reversed Numbers (SPOJ)
You can reverse a number like the following technique with numerical operation: #define ll long long ll reverse_num(ll N) { ll ret=0; while(N) { ret= (ret*10) + (N%10); N/=10; } return ret; } Another way of string operation to reverse a number: string s1; char st1[12]; sf("%s",st1); ll l1=strlen(st1); bool flag_0; //-----------to handle leading zero //------------------reverse number if(st1[l1-1]=='0') flag_0=1; else flag_0=0; for(ll i=l1-1;i>=0;i--...